'Creating Measures' Awkward-ness Task - Example #5 (solutions) Malcolm Swan Mathematics Education University of Nottingham Malcolm.Swan@nottingham.ac.uk Jim Ridgway School of Education University of Durham Jim.Ridgway@durham.ac.uk This problem gives you the chance to: · invent your own measure for the concept of "awkward-ness" · use your measure to put situations in order of "awkward-ness" · generalize your measure to work in different situations. ____________________________________________________ · Have you ever arrived at a packed theater after the show has started? · You have to make everyone stand while you squeeze past to take your seat. · Imagine that five people A, B, C, D and E each arrive to take their seat in a theater. · They are not allowed to take different seats to the one they have been allocated. This diagram shows the order in which they arrive and their seating positions: · So, D arrives first and sits in the second seat from the right hand end of the row. · Then E arrives. D has to stand up while E squeezes into the last seat in the row. · Then A arrives. She sits on the first seat of the row. · Now B arrives and makes A stand, while he takes the second seat in. · Finally C arrives and makes both A and B stand up while she takes her seat. Warm-up Try out this situation from different starting points using scraps of paper labeled A, B C, D and E until you can see what is happening. What is the most awkward situation you can devise? Draw it below: Here are four movie theater situations: Comment: The most awkard situation possible is shown below: In this situation, A sits first, then · A stands while B takes her place · A and B stand while C takes his place · A, B and C stand while D takes his place · A, B, C and D stand while E takes her place. 1. Place the four situations in order of "awkward-ness." · Which is the easiest situation for people? · Which is the most awkward? · Explain how you decided. Solution: The above measure is unsatisfactory because: The easiest situation is situation (3), because this results in only one person having to stand on one occasion (person D has to stand while E squeezes by). The most awkward situation is probably (4) because people have to stand on five occasions. (A has to stand while B sits down, then A, B, C and D all have to stand while E sits down.) 2. Invent a way of measuring "awkward-ness." This should give a number to each situation. Explain carefully how your method works. Solution for Questions 2 and 3: A suitable measure of "awkward-ness" would be to count the number of times a person makes someone stand up to let them pass. This would give, for situations 1 to 4: Number of times person makes someone else stand Situation A B C D E Total 1 0 1 2 0 1 4 2 0 0 2 3 3 8 3 0 0 0 0 1 1 4 0 1 0 0 4 5 Using the totals, we have, from least to most awkward: Situations 3, 1, 4 then 2. 3. Show how you can use your measure to place the four situations in order of "awkward-ness." Show all your work. 4. Adapt your measure so that the minimum value it can take is 0 (where no-one is made to stand up) and the maximum it can take is 1 (the most awkard situation possible). Solution: To make the measure range from 0 to 1, we could divide the totals above by the maximum possible "awkward-ness" score for five people = 10 (see Warm-up). 5. Show how your measure in part 4 may be generalised for any number of people entering a row. ( That is when n people enter a row with n available seats). Solution: If there was just one person, the maximum "awkward-ness" = 0. For 2 people, the maximum "awkward-ness" = 1. For 3 people, the maximum "awkward-ness" = 3 (= 1+2). For 4 people, the maximum "awkward-ness" = 6 (= 1+2+3). For 5 people, the maximum "awkward-ness" = 10 (= 1+2+3+4). ... For n people, the maximum "awkward-ness" = (= 1 + 2 + 3 + ... n). Thus, if s = The number of occasions on which people have to stand; we can define our measure of "awkward-ness" for a given situation to be: =